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Daddyman

Помогиете сформировать SQL запрос

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Вот запрос:

 

SELECT p.*, pd.*, m.name as 'm_name' 
FROM oc_product p 
LEFT JOIN oc_product_description pd ON (p.product_id = pd.product_id) 
LEFT JOIN oc_manufacturer m ON (p.manufacturer_id = m.manufacturer_id) 
WHERE pd.language_id = '1' 
GROUP BY p.product_id 
ORDER BY pd.name 
ASC LIMIT 0,20
 
Нужно чтобы этот запрос выдал только те результаты, которые в таблице oc_product_to_store в поле store_id равно 2-м. Сравнение нужно проводить по product_id.
 
Не силен в sql, пробовал сам, одни ошибки sql запросов(
Помогите пожалуйста)
 

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SELECT p.*, pd.*, m.name as 'm_name' 
FROM oc_product p 
LEFT JOIN oc_product_description pd ON (p.product_id = pd.product_id) 
LEFT JOIN oc_product_to_store p2s ON (p.product_id = p2s.product_id) 
LEFT JOIN oc_manufacturer m ON (p.manufacturer_id = m.manufacturer_id) 
WHERE pd.language_id = '1' AND p2s.store_id = '2'
GROUP BY p.product_id 
ORDER BY pd.name 
ASC LIMIT 0,20

Как то так

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Спасибо огромное!!! Работает!

Ух теперь бы всё это распихать по Моделям=))

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Подскажите пожалуйста, имеется запрос на вывод Артикула (SKU) товара в admin/model/sale/order.php, а как вывести туда же запрос на Расположение (location) товара?

 

public function getOrderProducts($order_id) {
$query = $this->db->query("SELECT a.*, b.sku FROM " . DB_PREFIX . "order_product a LEFT JOIN " . DB_PREFIX . "product b ON a.product_id = b.product_id WHERE order_id = '" . (int)$order_id . "'");
 
return $query->rows;
}

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Скорее всего так

$query = $this->db->query("SELECT a.*, b.sku, b.location FROM " . DB_PREFIX . "order_product a LEFT JOIN " . DB_PREFIX . "product b ON a.product_id = b.product_id WHERE order_id = '" . (int)$order_id . "'");

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