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[Решено] Как вытащить все ссылки на статьи в любое место шаблона ?

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Как вытащить все ссылки на статьи в любое место шаблона ?

Спасибо.

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<?php if ($informations) { ?>

<ul>

<?php foreach ($informations as $information) { ?>

<li><a href="<?php echo $information['href']; ?>"><?php echo $information['title']; ?></a></li>

<?php } ?>

</ul>

<?php } ?>

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Пытался так. Вставляю код в шапку. Получаю :

 
  • Notice: Undefined variable: informations in C:\xampp\htdocs\www\site\catalog\view\theme\default\template\common\header.tpl on line 133

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Ничего удивительного, контроллеру ничего не известно о переменной informations.

 

В catalog/controller/common/header.php перед:

		$this->load->model('catalog/category');
добавить:

		$this->load->model('catalog/information');

		$this->data['informations'] = array();

		foreach ($this->model_catalog_information->getInformations() as $result)
		{
			$this->data['informations'][] = array
			(
				'title' => $result['title'],
				'href'  => $this->url->link('information/information', 'information_id=' . $result['information_id'])
			);
		}

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условие

if ($result['bottom']) {
лишнее, ибо оно только для тех статей, которые отмечены для вывода в footer`е
  • +1 1

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Ничего удивительного, контроллеру ничего не известно о переменной informations.

 

В catalog/controller/common/header.php перед:

		$this->load->model('catalog/category');
добавить:

		$this->load->model('catalog/information');

		$this->data['informations'] = array();

		foreach ($this->model_catalog_information->getInformations() as $result)
		{
			$this->data['informations'][] = array
			(
				'title' => $result['title'],
				'href'  => $this->url->link('information/information', 'information_id=' . $result['information_id'])
			);
		}

СПАСИБО!!! Всё помогло :)

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