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unknown77

ускорение работы ошибки лога

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подскажите как с этим бороться?))

 

2015-10-09 21:19:22 - all_time: 0.07758; count_queries: 00031 /admin/index.php?route=catalog/advanced_product&token=10097d019a6636496ef056bfcc84f4a5&filter_category=107
2015-10-09 21:19:46 - all_time: 0.87438; count_queries: 00048 /admin/index.php?route=catalog/advanced_product/update&token=10097d019a6636496ef056bfcc84f4a5&product_id=992&filter_category=107
2015-10-09 21:19:47 - all_time: 0.00940; count_queries: 00008 /admin/index.php?route=extension/openbay/linkStatus&token=10097d019a6636496ef056bfcc84f4a5&product_id=992
2015-10-09 21:21:16 - 0.51702 SELECT * FROM oc_category c LEFT JOIN oc_category_description cd ON (c.category_id = cd.category_id) LEFT JOIN oc_category_to_store c2s ON (c.category_id = c2s.category_id) WHERE c.parent_id = '0' AND cd.language_id = '2' AND c2s.store_id = '0'  AND c.status = '1' ORDER BY c.sort_order, LCASE(cd.name)
2015-10-09 21:22:22 - 0.62032 SELECT * FROM oc_category c LEFT JOIN oc_category_description cd ON (c.category_id = cd.category_id) LEFT JOIN oc_category_to_store c2s ON (c.category_id = c2s.category_id) WHERE c.parent_id = '0' AND cd.language_id = '2' AND c2s.store_id = '0'  AND c.status = '1' ORDER BY c.sort_order, LCASE(cd.name)
2015-10-09 21:24:05 - 1.02467 SELECT COUNT(DISTINCT p.product_id) AS total FROM oc_category_path cp LEFT JOIN oc_product_to_category p2c ON (cp.category_id = p2c.category_id) LEFT JOIN oc_product p ON (p2c.product_id = p.product_id) LEFT JOIN oc_product_description pd ON (p.product_id = pd.product_id) LEFT JOIN oc_product_to_store p2s ON (p.product_id = p2s.product_id) WHERE pd.language_id = '2' AND p.status = '1' AND p.date_available <= NOW() AND p2s.store_id = '0' AND cp.path_id = '118'
2015-10-09 21:24:43 - 1.40380 SELECT * FROM oc_category c LEFT JOIN oc_category_description cd ON (c.category_id = cd.category_id) LEFT JOIN oc_category_to_store c2s ON (c.category_id = c2s.category_id) WHERE c.parent_id = '0' AND cd.language_id = '2' AND c2s.store_id = '0'  AND c.status = '1' ORDER BY c.sort_order, LCASE(cd.name)
2015-10-09 21:24:45 - 0.55863 SELECT * FROM oc_category c LEFT JOIN oc_category_description cd ON (c.category_id = cd.category_id) LEFT JOIN oc_category_to_store c2s ON (c.category_id = c2s.category_id) WHERE c.parent_id = '133' AND cd.language_id = '2' AND c2s.store_id = '0'  AND c.status = '1' ORDER BY c.sort_order, LCASE(cd.name)
2015-10-09 21:25:15 - 0.85104 SELECT COUNT(DISTINCT p.product_id) AS total FROM oc_category_path cp LEFT JOIN oc_product_to_category p2c ON (cp.category_id = p2c.category_id) LEFT JOIN oc_product p ON (p2c.product_id = p.product_id) LEFT JOIN oc_product_description pd ON (p.product_id = pd.product_id) LEFT JOIN oc_product_to_store p2s ON (p.product_id = p2s.product_id) WHERE pd.language_id = '2' AND p.status = '1' AND p.date_available <= NOW() AND p2s.store_id = '0' AND cp.path_id = '114'
2015-10-09 21:25:46 - 0.56017 SELECT * FROM oc_category c LEFT JOIN oc_category_description cd ON (c.category_id = cd.category_id) LEFT JOIN oc_category_to_store c2s ON (c.category_id = c2s.category_id) WHERE c.parent_id = '0' AND cd.language_id = '2' AND c2s.store_id = '0'  AND c.status = '1' ORDER BY c.sort_order, LCASE(cd.name)
 

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с чем именно?

про подсчет товаров в категориях на форуме писано-переписано.

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